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13440001004003 = 77972409034057
BaseRepresentation
bin1100001110010011111001…
…1111000101000111100011
31202120211222210000110000002
43003210332133011013203
53230200110224112003
644330130133050215
72555002516414340
oct303447637050743
952524883013002
1013440001004003
114311966206492
12161091918696b
1376650463aca2
143466dc9777c7
15184912bb4a88
hexc393e7c51e3

13440001004003 has 8 divisors (see below), whose sum is σ = 15379273426272. Its totient is φ = 11505546651456.

The previous prime is 13440001003999. The next prime is 13440001004039. The reversal of 13440001004003 is 30040010004431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13440001004003 - 22 = 13440001003999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13440001000003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1204511450 + ... + 1204522607.

It is an arithmetic number, because the mean of its divisors is an integer number (1922409178284).

Almost surely, 213440001004003 is an apocalyptic number.

13440001004003 is a deficient number, since it is larger than the sum of its proper divisors (1939272422269).

13440001004003 is an equidigital number, since it uses as much as digits as its factorization.

13440001004003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2409034861.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13440001004003 its reverse (30040010004431), we get a palindrome (43480011008434).

The spelling of 13440001004003 in words is "thirteen trillion, four hundred forty billion, one million, four thousand, three".

Divisors: 1 7 797 5579 2409034057 16863238399 1920000143429 13440001004003