13440014433 has 12 divisors (see below), whose sum is σ = 19456596900. Its totient is φ = 8940051456.

The previous prime is 13440014387. The next prime is 13440014437. The reversal of 13440014433 is 33441004431.

It can be written as a sum of positive squares in 2 ways, for example, as 8473570704 + 4966443729 = 92052^2 + 70473^2 .

It is not a de Polignac number, because 13440014433 - 2⁸ = 13440014177 is a prime.

It is a super-2 number, since 2×13440014433² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13440014397 and 13440014406.

It is not an unprimeable number, because it can be changed into a prime (13440014437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1658916 + ... + 1666997.

It is an arithmetic number, because the mean of its divisors is an integer number (1621383075).

Almost surely, 2^13440014433 is an apocalyptic number.

It is an amenable number.

13440014433 is a deficient number, since it is larger than the sum of its proper divisors (6016582467).

13440014433 is a wasteful number, since it uses less digits than its factorization.

13440014433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3326368 (or 3326365 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13440014433 its reverse (33441004431), we get a palindrome (46881018864).

The spelling of 13440014433 in words is "thirteen billion, four hundred forty million, fourteen thousand, four hundred thirty-three".