Base | Representation |
---|---|
bin | 1100001110010100000001… |
… | …0011001010010111110111 |
3 | 1202120212001220021110102120 |
4 | 3003211000103022113313 |
5 | 3230200141021343411 |
6 | 44330133141211023 |
7 | 2555003336154243 |
oct | 303450023122767 |
9 | 52525056243376 |
10 | 13440031434231 |
11 | 4311981400136 |
12 | 1610927400a73 |
13 | 76650aa33a3c |
14 | 346702a19423 |
15 | 1849156c6106 |
hex | c39404ca5f7 |
13440031434231 has 16 divisors (see below), whose sum is σ = 18436649151744. Its totient is φ = 8705381217984.
The previous prime is 13440031434211. The next prime is 13440031434241. The reversal of 13440031434231 is 13243413004431.
It is not a de Polignac number, because 13440031434231 - 25 = 13440031434199 is a prime.
It is a super-2 number, since 2×134400314342312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13440031434192 and 13440031434201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13440031434211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 457970451 + ... + 457999796.
It is an arithmetic number, because the mean of its divisors is an integer number (1152290571984).
Almost surely, 213440031434231 is an apocalyptic number.
13440031434231 is a deficient number, since it is larger than the sum of its proper divisors (4996617717513).
13440031434231 is an equidigital number, since it uses as much as digits as its factorization.
13440031434231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 915970390.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13440031434231 its reverse (13243413004431), we get a palindrome (26683444438662).
The spelling of 13440031434231 in words is "thirteen trillion, four hundred forty billion, thirty-one million, four hundred thirty-four thousand, two hundred thirty-one".
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