13440042312001 has 4 divisors (see below), whose sum is σ = 13447842686512. Its totient is φ = 13432241937492.

The previous prime is 13440042311957. The next prime is 13440042312023. The reversal of 13440042312001 is 10021324004431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440042312001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13440042312101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3900184671 + ... + 3900188116.

It is an arithmetic number, because the mean of its divisors is an integer number (3361960671628).

Almost surely, 2^{13440042312001} is an apocalyptic number.

It is an amenable number.

13440042312001 is a deficient number, since it is larger than the sum of its proper divisors (7800374511).

13440042312001 is an equidigital number, since it uses as much as digits as its factorization.

13440042312001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7800374510.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13440042312001 its reverse (10021324004431), we get a palindrome (23461366316432).

The spelling of 13440042312001 in words is "thirteen trillion, four hundred forty billion, forty-two million, three hundred twelve thousand, one".