Base | Representation |
---|---|
bin | 11001000010001011… |
… | …01100100110101001 |
3 | 1021200122210221120102 |
4 | 30201011230212221 |
5 | 210011122342213 |
6 | 10101350435145 |
7 | 654025325045 |
oct | 144105544651 |
9 | 37618727512 |
10 | 13440043433 |
11 | 5777610613 |
12 | 2731062ab5 |
13 | 13625c382b |
14 | 916d95025 |
15 | 539dc5158 |
hex | 32116c9a9 |
13440043433 has 4 divisors (see below), whose sum is σ = 14147414160. Its totient is φ = 12732672708.
The previous prime is 13440043427. The next prime is 13440043457. The reversal of 13440043433 is 33434004431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33434004431 = 17 ⋅1966706143.
It is a cyclic number.
It is not a de Polignac number, because 13440043433 - 212 = 13440039337 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13440043396 and 13440043405.
It is not an unprimeable number, because it can be changed into a prime (13440043403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353685335 + ... + 353685372.
It is an arithmetic number, because the mean of its divisors is an integer number (3536853540).
Almost surely, 213440043433 is an apocalyptic number.
It is an amenable number.
13440043433 is a deficient number, since it is larger than the sum of its proper divisors (707370727).
13440043433 is an equidigital number, since it uses as much as digits as its factorization.
13440043433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 707370726.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 13440043433 its reverse (33434004431), we get a palindrome (46874047864).
The spelling of 13440043433 in words is "thirteen billion, four hundred forty million, forty-three thousand, four hundred thirty-three".
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