1344011224489 has 2 divisors, whose sum is σ = 1344011224490. Its totient is φ = 1344011224488.

The previous prime is 1344011224483. The next prime is 1344011224499. The reversal of 1344011224489 is 9844221104431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1267218501264 + 76792723225 = 1125708^2 + 277115^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344011224489 - 2³³ = 1335421289897 is a prime.

It is a super-2 number, since 2×1344011224489² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1344011224483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005612244 + 672005612245.

It is an arithmetic number, because the mean of its divisors is an integer number (672005612245).

Almost surely, 2^{1344011224489} is an apocalyptic number.

It is an amenable number.

1344011224489 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344011224489 is an equidigital number, since it uses as much as digits as its factorization.

1344011224489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 43.

The spelling of 1344011224489 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred twenty-four thousand, four hundred eighty-nine".