1344011225521 has 4 divisors (see below), whose sum is σ = 1346889194352. Its totient is φ = 1341133256692.

The previous prime is 1344011225519. The next prime is 1344011225527. The reversal of 1344011225521 is 1255221104431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344011225521 - 2¹ = 1344011225519 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344011225527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438983715 + ... + 1438984648.

It is an arithmetic number, because the mean of its divisors is an integer number (336722298588).

Almost surely, 2^{1344011225521} is an apocalyptic number.

It is an amenable number.

1344011225521 is a deficient number, since it is larger than the sum of its proper divisors (2877968831).

1344011225521 is an equidigital number, since it uses as much as digits as its factorization.

1344011225521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2877968830.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 1344011225521 its reverse (1255221104431), we get a palindrome (2599232329952).

The spelling of 1344011225521 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred twenty-five thousand, five hundred twenty-one".