Base | Representation |
---|---|
bin | 10000000001011… |
… | …00110010110111 |
3 | 100100220021210111 |
4 | 20000230302313 |
5 | 233401314312 |
6 | 21200403451 |
7 | 3221251153 |
oct | 1000546267 |
9 | 310807714 |
10 | 134401207 |
11 | 69958686 |
12 | 39016587 |
13 | 21ac9b55 |
14 | 13bc8063 |
15 | bbec8a7 |
hex | 802ccb7 |
134401207 has 2 divisors, whose sum is σ = 134401208. Its totient is φ = 134401206.
The previous prime is 134401177. The next prime is 134401219. The reversal of 134401207 is 702104431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134401207 - 211 = 134399159 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134401807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200603 + 67200604.
It is an arithmetic number, because the mean of its divisors is an integer number (67200604).
Almost surely, 2134401207 is an apocalyptic number.
134401207 is a deficient number, since it is larger than the sum of its proper divisors (1).
134401207 is an equidigital number, since it uses as much as digits as its factorization.
134401207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 22.
The square root of 134401207 is about 11593.1534536553. The cubic root of 134401207 is about 512.2331993823.
Adding to 134401207 its reverse (702104431), we get a palindrome (836505638).
The spelling of 134401207 in words is "one hundred thirty-four million, four hundred one thousand, two hundred seven".
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