13440121 has 2 divisors, whose sum is σ = 13440122. Its totient is φ = 13440120.

The previous prime is 13440109. The next prime is 13440173. The reversal of 13440121 is 12104431.

13440121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13395600 + 44521 = 3660^2 + 211^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13440095 and 13440104.

It is not a weakly prime, because it can be changed into another prime (13440101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720060 + 6720061.

It is an arithmetic number, because the mean of its divisors is an integer number (6720061).

Almost surely, 2^13440121 is an apocalyptic number.

It is an amenable number.

13440121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440121 is an equidigital number, since it uses as much as digits as its factorization.

13440121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 13440121 is about 3666.0770586555. The cubic root of 13440121 is about 237.7575916149.

Adding to 13440121 its reverse (12104431), we get a palindrome (25544552).

The spelling of 13440121 in words is "thirteen million, four hundred forty thousand, one hundred twenty-one".