13440101 has 2 divisors, whose sum is σ = 13440102. Its totient is φ = 13440100.

The previous prime is 13440083. The next prime is 13440109. The reversal of 13440101 is 10104431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11937025 + 1503076 = 3455^2 + 1226^2 .

It is an emirp because it is prime and its reverse (10104431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13440101 - 2¹⁰ = 13439077 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13440109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720050 + 6720051.

It is an arithmetic number, because the mean of its divisors is an integer number (6720051).

Almost surely, 2^13440101 is an apocalyptic number.

It is an amenable number.

13440101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440101 is an equidigital number, since it uses as much as digits as its factorization.

13440101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 13440101 is about 3666.0743309431. The cubic root of 13440101 is about 237.7574736806.

Adding to 13440101 its reverse (10104431), we get a palindrome (23544532).

The spelling of 13440101 in words is "thirteen million, four hundred forty thousand, one hundred one".