134401300015261 has 4 divisors (see below), whose sum is σ = 134492050388124. Its totient is φ = 134310549642400.

The previous prime is 134401300015127. The next prime is 134401300015273. The reversal of 134401300015261 is 162510003104431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35304630732900 + 99096669282361 = 5941770^2 + 9954731^2 .

It is a cyclic number.

It is not a de Polignac number, because 134401300015261 - 2¹¹ = 134401300013213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401300013261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45375184210 + ... + 45375187171.

It is an arithmetic number, because the mean of its divisors is an integer number (33623012597031).

Almost surely, 2^{134401300015261} is an apocalyptic number.

It is an amenable number.

134401300015261 is a deficient number, since it is larger than the sum of its proper divisors (90750372863).

134401300015261 is an equidigital number, since it uses as much as digits as its factorization.

134401300015261 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90750372862.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 134401300015261 its reverse (162510003104431), we get a palindrome (296911303119692).

The spelling of 134401300015261 in words is "one hundred thirty-four trillion, four hundred one billion, three hundred million, fifteen thousand, two hundred sixty-one".