Base | Representation |
---|---|
bin | 11001000010001100… |
… | …00010000000110010 |
3 | 1021200122222101212011 |
4 | 30201012002000302 |
5 | 210011133143442 |
6 | 10101352353134 |
7 | 654026141515 |
oct | 144106020062 |
9 | 37618871764 |
10 | 13440131122 |
11 | 5777670490 |
12 | 27310a57aa |
13 | 1362624712 |
14 | 916db8d7c |
15 | 539de1117 |
hex | 321182032 |
13440131122 has 8 divisors (see below), whose sum is σ = 21992941872. Its totient is φ = 6109150500.
The previous prime is 13440131093. The next prime is 13440131123. The reversal of 13440131122 is 22113104431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Harshad number since it is a multiple of its sum of digits (22), and also a Moran number because the ratio is a prime number: 610915051 = 13440131122 / (1 + 3 + 4 + 4 + 0 + 1 + 3 + 1 + 1 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 13440131093 and 13440131102.
It is not an unprimeable number, because it can be changed into a prime (13440131123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305457504 + ... + 305457547.
It is an arithmetic number, because the mean of its divisors is an integer number (2749117734).
Almost surely, 213440131122 is an apocalyptic number.
13440131122 is a deficient number, since it is larger than the sum of its proper divisors (8552810750).
13440131122 is a wasteful number, since it uses less digits than its factorization.
13440131122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 610915064.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13440131122 its reverse (22113104431), we get a palindrome (35553235553).
The spelling of 13440131122 in words is "thirteen billion, four hundred forty million, one hundred thirty-one thousand, one hundred twenty-two".
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