13440132342541 has 4 divisors (see below), whose sum is σ = 13873684998784. Its totient is φ = 13006579686300.

The previous prime is 13440132342487. The next prime is 13440132342589. The reversal of 13440132342541 is 14524323104431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13440132342541 - 2²³ = 13440123953933 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13440132342541.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440132342641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216776328075 + ... + 216776328136.

It is an arithmetic number, because the mean of its divisors is an integer number (3468421249696).

Almost surely, 2^{13440132342541} is an apocalyptic number.

It is an amenable number.

13440132342541 is a deficient number, since it is larger than the sum of its proper divisors (433552656243).

13440132342541 is an equidigital number, since it uses as much as digits as its factorization.

13440132342541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433552656242.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 13440132342541 its reverse (14524323104431), we get a palindrome (27964455446972).

The spelling of 13440132342541 in words is "thirteen trillion, four hundred forty billion, one hundred thirty-two million, three hundred forty-two thousand, five hundred forty-one".