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13440225541 = 33140604911
BaseRepresentation
bin11001000010001100…
…11001000100000101
31021200200011012101011
430201012121010011
5210011144204131
610101354402221
7654030014011
oct144106310405
937620135334
1013440225541
115777725416
122731130371
1313626586a2
14917001541
15539e0e0b1
hex321199105

13440225541 has 4 divisors (see below), whose sum is σ = 13480830784. Its totient is φ = 13399620300.

The previous prime is 13440225511. The next prime is 13440225563. The reversal of 13440225541 is 14552204431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14552204431 = 24160382591.

It is a cyclic number.

It is not a de Polignac number, because 13440225541 - 25 = 13440225509 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440225511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20302125 + ... + 20302786.

It is an arithmetic number, because the mean of its divisors is an integer number (3370207696).

Almost surely, 213440225541 is an apocalyptic number.

It is an amenable number.

13440225541 is a deficient number, since it is larger than the sum of its proper divisors (40605243).

13440225541 is an equidigital number, since it uses as much as digits as its factorization.

13440225541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40605242.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 13440225541 its reverse (14552204431), we get a palindrome (27992429972).

The spelling of 13440225541 in words is "thirteen billion, four hundred forty million, two hundred twenty-five thousand, five hundred forty-one".

Divisors: 1 331 40604911 13440225541