1344023121431 has 4 divisors (see below), whose sum is σ = 1344085334664. Its totient is φ = 1343960908200.

The previous prime is 1344023121409. The next prime is 1344023121499. The reversal of 1344023121431 is 1341213204431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344023121431 is a prime.

It is a super-2 number, since 2×1344023121431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344023121394 and 1344023121403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344023129431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31074200 + ... + 31117421.

It is an arithmetic number, because the mean of its divisors is an integer number (336021333666).

Almost surely, 2^{1344023121431} is an apocalyptic number.

1344023121431 is a deficient number, since it is larger than the sum of its proper divisors (62213233).

1344023121431 is an equidigital number, since it uses as much as digits as its factorization.

1344023121431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62213232.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1344023121431 its reverse (1341213204431), we get a palindrome (2685236325862).

The spelling of 1344023121431 in words is "one trillion, three hundred forty-four billion, twenty-three million, one hundred twenty-one thousand, four hundred thirty-one".