Base | Representation |
---|---|
bin | 111110100101100001… |
… | …0110110010101110001 |
3 | 110211220210000001101201 |
4 | 1331023002312111301 |
5 | 4200224133233431 |
6 | 141424403131201 |
7 | 12465426566503 |
oct | 1751302662561 |
9 | 424823001351 |
10 | 134403024241 |
11 | 52000004442 |
12 | 2206b373b01 |
13 | c89c156215 |
14 | 671016dd73 |
15 | 3769698461 |
hex | 1f4b0b6571 |
134403024241 has 2 divisors, whose sum is σ = 134403024242. Its totient is φ = 134403024240.
The previous prime is 134403024221. The next prime is 134403024269. The reversal of 134403024241 is 142420304431.
It is an a-pointer prime, because the next prime (134403024269) can be obtained adding 134403024241 to its sum of digits (28).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131116410000 + 3286614241 = 362100^2 + 57329^2 .
It is a cyclic number.
It is not a de Polignac number, because 134403024241 - 223 = 134394635633 is a prime.
It is not a weakly prime, because it can be changed into another prime (134403024221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67201512120 + 67201512121.
It is an arithmetic number, because the mean of its divisors is an integer number (67201512121).
Almost surely, 2134403024241 is an apocalyptic number.
It is an amenable number.
134403024241 is a deficient number, since it is larger than the sum of its proper divisors (1).
134403024241 is an equidigital number, since it uses as much as digits as its factorization.
134403024241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 134403024241 its reverse (142420304431), we get a palindrome (276823328672).
The spelling of 134403024241 in words is "one hundred thirty-four billion, four hundred three million, twenty-four thousand, two hundred forty-one".
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