13440330131 has 4 divisors (see below), whose sum is σ = 13752895992. Its totient is φ = 13127764272.

The previous prime is 13440330121. The next prime is 13440330133. The reversal of 13440330131 is 13103304431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440330131 is a prime.

It is a super-2 number, since 2×13440330131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13440330097 and 13440330106.

It is not an unprimeable number, because it can be changed into a prime (13440330133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156282866 + ... + 156282951.

It is an arithmetic number, because the mean of its divisors is an integer number (3438223998).

Almost surely, 2^13440330131 is an apocalyptic number.

13440330131 is a deficient number, since it is larger than the sum of its proper divisors (312565861).

13440330131 is an equidigital number, since it uses as much as digits as its factorization.

13440330131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312565860.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13440330131 its reverse (13103304431), we get a palindrome (26543634562).

The spelling of 13440330131 in words is "thirteen billion, four hundred forty million, three hundred thirty thousand, one hundred thirty-one".