134403433111 has 8 divisors (see below), whose sum is σ = 138172114944. Its totient is φ = 130672627800.

The previous prime is 134403433097. The next prime is 134403433139. The reversal of 134403433111 is 111334304431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134403433111 - 2⁵ = 134403433079 is a prime.

It is a super-2 number, since 2×134403433111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134403433111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134403433511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9461935 + ... + 9476128.

It is an arithmetic number, because the mean of its divisors is an integer number (17271514368).

Almost surely, 2^134403433111 is an apocalyptic number.

134403433111 is a deficient number, since it is larger than the sum of its proper divisors (3768681833).

134403433111 is a wasteful number, since it uses less digits than its factorization.

134403433111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18938261.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 134403433111 its reverse (111334304431), we get a palindrome (245737737542).

The spelling of 134403433111 in words is "one hundred thirty-four billion, four hundred three million, four hundred thirty-three thousand, one hundred eleven".