13440350533 has 2 divisors, whose sum is σ = 13440350534. Its totient is φ = 13440350532.

The previous prime is 13440350489. The next prime is 13440350563. The reversal of 13440350533 is 33505304431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11057153409 + 2383197124 = 105153^2 + 48818^2 .

It is an emirp because it is prime and its reverse (33505304431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13440350533 - 2¹⁷ = 13440219461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13440350495 and 13440350504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13440350563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720175266 + 6720175267.

It is an arithmetic number, because the mean of its divisors is an integer number (6720175267).

Almost surely, 2^13440350533 is an apocalyptic number.

It is an amenable number.

13440350533 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440350533 is an equidigital number, since it uses as much as digits as its factorization.

13440350533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 13440350533 its reverse (33505304431), we get a palindrome (46945654964).

The spelling of 13440350533 in words is "thirteen billion, four hundred forty million, three hundred fifty thousand, five hundred thirty-three".