Base | Representation |
---|---|
bin | 10011100011101111001… |
… | …010100001101100010111 |
3 | 11202111012121201122011111 |
4 | 103203233022201230113 |
5 | 134010044312413143 |
6 | 2505240003115451 |
7 | 166050423065641 |
oct | 23435712415427 |
9 | 4674177648144 |
10 | 1344042310423 |
11 | 47900693294a |
12 | 198599072b87 |
13 | 99986793757 |
14 | 490a2961891 |
15 | 24e6573d99d |
hex | 138ef2a1b17 |
1344042310423 has 2 divisors, whose sum is σ = 1344042310424. Its totient is φ = 1344042310422.
The previous prime is 1344042310291. The next prime is 1344042310469. The reversal of 1344042310423 is 3240132404431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344042310423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344042310123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672021155211 + 672021155212.
It is an arithmetic number, because the mean of its divisors is an integer number (672021155212).
Almost surely, 21344042310423 is an apocalyptic number.
1344042310423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344042310423 is an equidigital number, since it uses as much as digits as its factorization.
1344042310423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1344042310423 its reverse (3240132404431), we get a palindrome (4584174714854).
The spelling of 1344042310423 in words is "one trillion, three hundred forty-four billion, forty-two million, three hundred ten thousand, four hundred twenty-three".
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