134410144115231 has 2 divisors, whose sum is σ = 134410144115232. Its totient is φ = 134410144115230.

The previous prime is 134410144115179. The next prime is 134410144115243. The reversal of 134410144115231 is 132511441014431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134410144115231 is a prime.

It is a super-2 number, since 2×134410144115231² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134410144115191 and 134410144115200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134410144118231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67205072057615 + 67205072057616.

It is an arithmetic number, because the mean of its divisors is an integer number (67205072057616).

Almost surely, 2^{134410144115231} is an apocalyptic number.

134410144115231 is a deficient number, since it is larger than the sum of its proper divisors (1).

134410144115231 is an equidigital number, since it uses as much as digits as its factorization.

134410144115231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 35.

Adding to 134410144115231 its reverse (132511441014431), we get a palindrome (266921585129662).

The spelling of 134410144115231 in words is "one hundred thirty-four trillion, four hundred ten billion, one hundred forty-four million, one hundred fifteen thousand, two hundred thirty-one".