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134410221201323 is a prime number
BaseRepresentation
bin11110100011111011010001…
…011111010010011110101011
3122121220111021102021011222202
4132203323101133102132223
5120104134113111420243
61153511111520010415
740211550403326434
oct3643732137223653
9577814242234882
10134410221201323
113991106688a011
12130a9727160a0b
1359ccaa2477872
1425296bcd6448b
1510814b94514b8
hex7a3ed17d27ab

134410221201323 has 2 divisors, whose sum is σ = 134410221201324. Its totient is φ = 134410221201322.

The previous prime is 134410221201287. The next prime is 134410221201337. The reversal of 134410221201323 is 323102122014431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134410221201323 - 218 = 134410220939179 is a prime.

It is a super-2 number, since 2×1344102212013232 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (134410221201353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67205110600661 + 67205110600662.

It is an arithmetic number, because the mean of its divisors is an integer number (67205110600662).

Almost surely, 2134410221201323 is an apocalyptic number.

134410221201323 is a deficient number, since it is larger than the sum of its proper divisors (1).

134410221201323 is an equidigital number, since it uses as much as digits as its factorization.

134410221201323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 134410221201323 its reverse (323102122014431), we get a palindrome (457512343215754).

The spelling of 134410221201323 in words is "one hundred thirty-four trillion, four hundred ten billion, two hundred twenty-one million, two hundred one thousand, three hundred twenty-three".