Base | Representation |
---|---|
bin | 1100001110011000000100… |
… | …1100001101100101100011 |
3 | 1202120221212202212000012221 |
4 | 3003212001030031211203 |
5 | 3230204403223201202 |
6 | 44330433151531511 |
7 | 2555042326013452 |
oct | 303460114154543 |
9 | 52527782760187 |
10 | 13441120131427 |
11 | 431238a9a548a |
12 | 1610b8bb29b97 |
13 | 766652457b71 |
14 | 3467a7454b99 |
15 | 18497b078037 |
hex | c398130d963 |
13441120131427 has 2 divisors, whose sum is σ = 13441120131428. Its totient is φ = 13441120131426.
The previous prime is 13441120131401. The next prime is 13441120131431. The reversal of 13441120131427 is 72413102114431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13441120131427 - 211 = 13441120129379 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13441120131392 and 13441120131401.
It is not a weakly prime, because it can be changed into another prime (13441120131457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560065713 + 6720560065714.
It is an arithmetic number, because the mean of its divisors is an integer number (6720560065714).
Almost surely, 213441120131427 is an apocalyptic number.
13441120131427 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441120131427 is an equidigital number, since it uses as much as digits as its factorization.
13441120131427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 13441120131427 its reverse (72413102114431), we get a palindrome (85854222245858).
The spelling of 13441120131427 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty million, one hundred thirty-one thousand, four hundred twenty-seven".
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