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13441120131427 is a prime number
BaseRepresentation
bin1100001110011000000100…
…1100001101100101100011
31202120221212202212000012221
43003212001030031211203
53230204403223201202
644330433151531511
72555042326013452
oct303460114154543
952527782760187
1013441120131427
11431238a9a548a
121610b8bb29b97
13766652457b71
143467a7454b99
1518497b078037
hexc398130d963

13441120131427 has 2 divisors, whose sum is σ = 13441120131428. Its totient is φ = 13441120131426.

The previous prime is 13441120131401. The next prime is 13441120131431. The reversal of 13441120131427 is 72413102114431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13441120131427 - 211 = 13441120129379 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13441120131392 and 13441120131401.

It is not a weakly prime, because it can be changed into another prime (13441120131457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560065713 + 6720560065714.

It is an arithmetic number, because the mean of its divisors is an integer number (6720560065714).

Almost surely, 213441120131427 is an apocalyptic number.

13441120131427 is a deficient number, since it is larger than the sum of its proper divisors (1).

13441120131427 is an equidigital number, since it uses as much as digits as its factorization.

13441120131427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 13441120131427 its reverse (72413102114431), we get a palindrome (85854222245858).

The spelling of 13441120131427 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty million, one hundred thirty-one thousand, four hundred twenty-seven".