Base | Representation |
---|---|
bin | 111110100101110001… |
… | …1000000110010010010 |
3 | 110211221100212102002112 |
4 | 1331023203000302102 |
5 | 4200233313040014 |
6 | 141425303545322 |
7 | 12465561344021 |
oct | 1751343006222 |
9 | 424840772075 |
10 | 134411455634 |
11 | 52004843035 |
12 | 2207215b242 |
13 | c8a0b18b01 |
14 | 67113268b8 |
15 | 376a2b173e |
hex | 1f4b8c0c92 |
134411455634 has 4 divisors (see below), whose sum is σ = 201617183454. Its totient is φ = 67205727816.
The previous prime is 134411455631. The next prime is 134411455637. The reversal of 134411455634 is 436554114431.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (134411455631) and next prime (134411455637).
It can be written as a sum of positive squares in only one way, i.e., 83432589409 + 50978866225 = 288847^2 + 225785^2 .
It is a junction number, because it is equal to n+sod(n) for n = 134411455591 and 134411455600.
It is not an unprimeable number, because it can be changed into a prime (134411455631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33602863907 + ... + 33602863910.
Almost surely, 2134411455634 is an apocalyptic number.
134411455634 is a deficient number, since it is larger than the sum of its proper divisors (67205727820).
134411455634 is an equidigital number, since it uses as much as digits as its factorization.
134411455634 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67205727819.
The product of its digits is 345600, while the sum is 41.
The spelling of 134411455634 in words is "one hundred thirty-four billion, four hundred eleven million, four hundred fifty-five thousand, six hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •