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134411455634 = 267205727817
BaseRepresentation
bin111110100101110001…
…1000000110010010010
3110211221100212102002112
41331023203000302102
54200233313040014
6141425303545322
712465561344021
oct1751343006222
9424840772075
10134411455634
1152004843035
122207215b242
13c8a0b18b01
1467113268b8
15376a2b173e
hex1f4b8c0c92

134411455634 has 4 divisors (see below), whose sum is σ = 201617183454. Its totient is φ = 67205727816.

The previous prime is 134411455631. The next prime is 134411455637. The reversal of 134411455634 is 436554114431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (134411455631) and next prime (134411455637).

It can be written as a sum of positive squares in only one way, i.e., 83432589409 + 50978866225 = 288847^2 + 225785^2 .

It is a junction number, because it is equal to n+sod(n) for n = 134411455591 and 134411455600.

It is not an unprimeable number, because it can be changed into a prime (134411455631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33602863907 + ... + 33602863910.

Almost surely, 2134411455634 is an apocalyptic number.

134411455634 is a deficient number, since it is larger than the sum of its proper divisors (67205727820).

134411455634 is an equidigital number, since it uses as much as digits as its factorization.

134411455634 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67205727819.

The product of its digits is 345600, while the sum is 41.

The spelling of 134411455634 in words is "one hundred thirty-four billion, four hundred eleven million, four hundred fifty-five thousand, six hundred thirty-four".

Divisors: 1 2 67205727817 134411455634