Base | Representation |
---|---|
bin | 11001000010010100… |
… | …01001101100010001 |
3 | 1021200202000021101022 |
4 | 30201022021230101 |
5 | 210011422224103 |
6 | 10101431445225 |
7 | 654041260346 |
oct | 144112115421 |
9 | 37622007338 |
10 | 13441211153 |
11 | 5778238977 |
12 | 2731526815 |
13 | 13629121a6 |
14 | 9171ba7cd |
15 | 53a056138 |
hex | 321289b11 |
13441211153 has 2 divisors, whose sum is σ = 13441211154. Its totient is φ = 13441211152.
The previous prime is 13441211141. The next prime is 13441211191. The reversal of 13441211153 is 35111214431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7637361664 + 5803849489 = 87392^2 + 76183^2 .
It is a cyclic number.
It is not a de Polignac number, because 13441211153 - 24 = 13441211137 is a prime.
It is not a weakly prime, because it can be changed into another prime (13441211053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720605576 + 6720605577.
It is an arithmetic number, because the mean of its divisors is an integer number (6720605577).
Almost surely, 213441211153 is an apocalyptic number.
It is an amenable number.
13441211153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441211153 is an equidigital number, since it uses as much as digits as its factorization.
13441211153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 26.
Adding to 13441211153 its reverse (35111214431), we get a palindrome (48552425584).
The spelling of 13441211153 in words is "thirteen billion, four hundred forty-one million, two hundred eleven thousand, one hundred fifty-three".
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