Base | Representation |
---|---|
bin | 11001000010010100… |
… | …10001010100100011 |
3 | 1021200202001212020201 |
4 | 30201022101110203 |
5 | 210011424224103 |
6 | 10101432250031 |
7 | 654041450431 |
oct | 144112212443 |
9 | 37622055221 |
10 | 13441242403 |
11 | 577825a3a6 |
12 | 2731540917 |
13 | 1362923494 |
14 | 9171c7d51 |
15 | 53a06051d |
hex | 321291523 |
13441242403 has 4 divisors (see below), whose sum is σ = 13441782168. Its totient is φ = 13440702640.
The previous prime is 13441242379. The next prime is 13441242431. The reversal of 13441242403 is 30424214431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13441242403 - 217 = 13441111331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13441242433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 230626 + ... + 282967.
It is an arithmetic number, because the mean of its divisors is an integer number (3360445542).
Almost surely, 213441242403 is an apocalyptic number.
13441242403 is a deficient number, since it is larger than the sum of its proper divisors (539765).
13441242403 is an equidigital number, since it uses as much as digits as its factorization.
13441242403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 539764.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 13441242403 its reverse (30424214431), we get a palindrome (43865456834).
The spelling of 13441242403 in words is "thirteen billion, four hundred forty-one million, two hundred forty-two thousand, four hundred three".
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