1344126113401 has 2 divisors, whose sum is σ = 1344126113402. Its totient is φ = 1344126113400.

The previous prime is 1344126113399. The next prime is 1344126113411. The reversal of 1344126113401 is 1043116214431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1173018963600 + 171107149801 = 1083060^2 + 413651^2 .

It is an emirp because it is prime and its reverse (1043116214431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344126113401 - 2¹ = 1344126113399 is a prime.

Together with 1344126113399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1344126113411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672063056700 + 672063056701.

It is an arithmetic number, because the mean of its divisors is an integer number (672063056701).

Almost surely, 2^{1344126113401} is an apocalyptic number.

It is an amenable number.

1344126113401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344126113401 is an equidigital number, since it uses as much as digits as its factorization.

1344126113401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 1344126113401 in words is "one trillion, three hundred forty-four billion, one hundred twenty-six million, one hundred thirteen thousand, four hundred one".