Base | Representation |
---|---|
bin | 111110100101110101… |
… | …0100011000110100011 |
3 | 110211221111120210001202 |
4 | 1331023222203012203 |
5 | 4200234314244303 |
6 | 141425414151415 |
7 | 12465614212502 |
oct | 1751352430643 |
9 | 424844523052 |
10 | 134413431203 |
11 | 52005972337 |
12 | 2207295256b |
13 | c8a135b09c |
14 | 67116bc839 |
15 | 376a551c88 |
hex | 1f4baa31a3 |
134413431203 has 4 divisors (see below), whose sum is σ = 134415680328. Its totient is φ = 134411182080.
The previous prime is 134413431199. The next prime is 134413431241. The reversal of 134413431203 is 302134314431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134413431203 - 22 = 134413431199 is a prime.
It is a super-2 number, since 2×1344134312032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134413431263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1032401 + ... + 1155282.
It is an arithmetic number, because the mean of its divisors is an integer number (33603920082).
Almost surely, 2134413431203 is an apocalyptic number.
134413431203 is a deficient number, since it is larger than the sum of its proper divisors (2249125).
134413431203 is an equidigital number, since it uses as much as digits as its factorization.
134413431203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2249124.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 134413431203 its reverse (302134314431), we get a palindrome (436547745634).
The spelling of 134413431203 in words is "one hundred thirty-four billion, four hundred thirteen million, four hundred thirty-one thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •