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1344141443400 = 2335273110323667
BaseRepresentation
bin10011100011110101000…
…100101100000101001000
311202111110112021010001020
4103203311010230011020
5134010300202142100
62505253503552440
7166053035520240
oct23436504540510
94674415233036
101344141443400
11479057891a28
121986062bb720
13999a1192712
14490b1ba8b20
1524e6e2c15a0
hex138f512c148

1344141443400 has 192 divisors, whose sum is σ = 4915717754880. Its totient is φ = 297321580800.

The previous prime is 1344141443389. The next prime is 1344141443441. The reversal of 1344141443400 is 43441414431.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5031634 + ... + 5292033.

It is an arithmetic number, because the mean of its divisors is an integer number (25602696640).

Almost surely, 21344141443400 is an apocalyptic number.

1344141443400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1344141443400 is an abundant number, since it is smaller than the sum of its proper divisors (3571576311480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1344141443400 is a wasteful number, since it uses less digits than its factorization.

1344141443400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10323724 (or 10323715 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 1344141443400 its reverse (43441414431), we get a palindrome (1387582857831).

The spelling of 1344141443400 in words is "one trillion, three hundred forty-four billion, one hundred forty-one million, four hundred forty-three thousand, four hundred".