13441440401 has 4 divisors (see below), whose sum is σ = 13804722612. Its totient is φ = 13078158192.

The previous prime is 13441440379. The next prime is 13441440409. The reversal of 13441440401 is 10404414431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6876389776 + 6565050625 = 82924^2 + 81025^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13441440401 is a prime.

It is a super-3 number, since 3×13441440401³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13441440409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181641050 + ... + 181641123.

It is an arithmetic number, because the mean of its divisors is an integer number (3451180653).

Almost surely, 2^13441440401 is an apocalyptic number.

It is an amenable number.

13441440401 is a deficient number, since it is larger than the sum of its proper divisors (363282211).

13441440401 is an equidigital number, since it uses as much as digits as its factorization.

13441440401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 363282210.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 13441440401 its reverse (10404414431), we get a palindrome (23845854832).

The spelling of 13441440401 in words is "thirteen billion, four hundred forty-one million, four hundred forty thousand, four hundred one".