Base | Representation |
---|---|
bin | 10011100011111000111… |
… | …000110100110001100011 |
3 | 11202111121222200120211012 |
4 | 103203320320310301203 |
5 | 134010413043122042 |
6 | 2505304111411135 |
7 | 166054443510431 |
oct | 23437070646143 |
9 | 4674558616735 |
10 | 1344205442147 |
11 | 47908aa24157 |
12 | 198623823aab |
13 | 999b150c7b9 |
14 | 490ba4a7d51 |
15 | 24e74c13e82 |
hex | 138f8e34c63 |
1344205442147 has 2 divisors, whose sum is σ = 1344205442148. Its totient is φ = 1344205442146.
The previous prime is 1344205442051. The next prime is 1344205442161. The reversal of 1344205442147 is 7412445024431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344205442147 is a prime.
It is a super-2 number, since 2×13442054421472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1344205442947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672102721073 + 672102721074.
It is an arithmetic number, because the mean of its divisors is an integer number (672102721074).
Almost surely, 21344205442147 is an apocalyptic number.
1344205442147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344205442147 is an equidigital number, since it uses as much as digits as its factorization.
1344205442147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 430080, while the sum is 41.
The spelling of 1344205442147 in words is "one trillion, three hundred forty-four billion, two hundred five million, four hundred forty-two thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •