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1344205442147 is a prime number
BaseRepresentation
bin10011100011111000111…
…000110100110001100011
311202111121222200120211012
4103203320320310301203
5134010413043122042
62505304111411135
7166054443510431
oct23437070646143
94674558616735
101344205442147
1147908aa24157
12198623823aab
13999b150c7b9
14490ba4a7d51
1524e74c13e82
hex138f8e34c63

1344205442147 has 2 divisors, whose sum is σ = 1344205442148. Its totient is φ = 1344205442146.

The previous prime is 1344205442051. The next prime is 1344205442161. The reversal of 1344205442147 is 7412445024431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344205442147 is a prime.

It is a super-2 number, since 2×13442054421472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1344205442947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672102721073 + 672102721074.

It is an arithmetic number, because the mean of its divisors is an integer number (672102721074).

Almost surely, 21344205442147 is an apocalyptic number.

1344205442147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344205442147 is an equidigital number, since it uses as much as digits as its factorization.

1344205442147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 430080, while the sum is 41.

The spelling of 1344205442147 in words is "one trillion, three hundred forty-four billion, two hundred five million, four hundred forty-two thousand, one hundred forty-seven".