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134421124003 = 673199734211
BaseRepresentation
bin111110100110000011…
…1111001001110100011
3110211222001001121121021
41331030013321032203
54200243301432003
6141430251110311
712466036462465
oct1751407711643
9424861047537
10134421124003
115200a247021
1222075442397
13c8a2b2273a
146712722135
15376b0712bd
hex1f4c1f93a3

134421124003 has 4 divisors (see below), whose sum is σ = 134620858888. Its totient is φ = 134221389120.

The previous prime is 134421123983. The next prime is 134421124051. The reversal of 134421124003 is 300421124431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134421124003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134421124063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99866433 + ... + 99867778.

It is an arithmetic number, because the mean of its divisors is an integer number (33655214722).

Almost surely, 2134421124003 is an apocalyptic number.

134421124003 is a deficient number, since it is larger than the sum of its proper divisors (199734885).

134421124003 is an equidigital number, since it uses as much as digits as its factorization.

134421124003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199734884.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134421124003 its reverse (300421124431), we get a palindrome (434842248434).

The spelling of 134421124003 in words is "one hundred thirty-four billion, four hundred twenty-one million, one hundred twenty-four thousand, three".

Divisors: 1 673 199734211 134421124003