Base | Representation |
---|---|
bin | 111110100110000011… |
… | …1111001001111010011 |
3 | 110211222001001121200001 |
4 | 1331030013321033103 |
5 | 4200243301432201 |
6 | 141430251110431 |
7 | 12466036462564 |
oct | 1751407711723 |
9 | 424861047601 |
10 | 134421124051 |
11 | 5200a247065 |
12 | 22075442417 |
13 | c8a2b22776 |
14 | 671272216b |
15 | 376b071301 |
hex | 1f4c1f93d3 |
134421124051 has 2 divisors, whose sum is σ = 134421124052. Its totient is φ = 134421124050.
The previous prime is 134421123983. The next prime is 134421124063. The reversal of 134421124051 is 150421124431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134421124051 - 213 = 134421115859 is a prime.
It is a super-2 number, since 2×1344211240512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134421124091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67210562025 + 67210562026.
It is an arithmetic number, because the mean of its divisors is an integer number (67210562026).
Almost surely, 2134421124051 is an apocalyptic number.
134421124051 is a deficient number, since it is larger than the sum of its proper divisors (1).
134421124051 is an equidigital number, since it uses as much as digits as its factorization.
134421124051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 134421124051 its reverse (150421124431), we get a palindrome (284842248482).
The spelling of 134421124051 in words is "one hundred thirty-four billion, four hundred twenty-one million, one hundred twenty-four thousand, fifty-one".
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