13442112403 has 2 divisors, whose sum is σ = 13442112404. Its totient is φ = 13442112402.

The previous prime is 13442112389. The next prime is 13442112421. The reversal of 13442112403 is 30421124431.

13442112403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30421124431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13442112403 is a prime.

It is not a weakly prime, because it can be changed into another prime (13442112493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721056201 + 6721056202.

It is an arithmetic number, because the mean of its divisors is an integer number (6721056202).

Almost surely, 2^13442112403 is an apocalyptic number.

13442112403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442112403 is an equidigital number, since it uses as much as digits as its factorization.

13442112403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13442112403 its reverse (30421124431), we get a palindrome (43863236834).

The spelling of 13442112403 in words is "thirteen billion, four hundred forty-two million, one hundred twelve thousand, four hundred three".