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134422412101 = 433126102607
BaseRepresentation
bin111110100110000110…
…0110011101101000101
3110211222010111001112121
41331030030303231011
54200244114141401
6141430334445541
712466053436045
oct1751414635505
9424863431477
10134422412101
115200aa4686a
12220759638b1
13c8a3183b23
146712979725
15376b227ca1
hex1f4c333b45

134422412101 has 4 divisors (see below), whose sum is σ = 137548514752. Its totient is φ = 131296309452.

The previous prime is 134422412017. The next prime is 134422412119. The reversal of 134422412101 is 101214224431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 101214224431 = 541187087291.

It is a cyclic number.

It is not a de Polignac number, because 134422412101 - 219 = 134421887813 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134422418101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1563051261 + ... + 1563051346.

It is an arithmetic number, because the mean of its divisors is an integer number (34387128688).

Almost surely, 2134422412101 is an apocalyptic number.

It is an amenable number.

134422412101 is a deficient number, since it is larger than the sum of its proper divisors (3126102651).

134422412101 is an equidigital number, since it uses as much as digits as its factorization.

134422412101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3126102650.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 134422412101 its reverse (101214224431), we get a palindrome (235636636532).

The spelling of 134422412101 in words is "one hundred thirty-four billion, four hundred twenty-two million, four hundred twelve thousand, one hundred one".

Divisors: 1 43 3126102607 134422412101