Base | Representation |
---|---|
bin | 1100001110011100100011… |
… | …1001110001000010011110 |
3 | 1202121001222121202001010002 |
4 | 3003213020321301002132 |
5 | 3230214334223133304 |
6 | 44331152411014302 |
7 | 2555114205262622 |
oct | 303471071610236 |
9 | 52531877661102 |
10 | 13442323255454 |
11 | 4312948045365 |
12 | 1611266a3a392 |
13 | 7667b47a4282 |
14 | 34687d159182 |
15 | 1849eb9ce31e |
hex | c39c8e7109e |
13442323255454 has 4 divisors (see below), whose sum is σ = 20163484883184. Its totient is φ = 6721161627726.
The previous prime is 13442323255429. The next prime is 13442323255469. The reversal of 13442323255454 is 45455232324431.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×134423232554542 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13442323255399 and 13442323255408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360580813862 + ... + 3360580813865.
It is an arithmetic number, because the mean of its divisors is an integer number (5040871220796).
Almost surely, 213442323255454 is an apocalyptic number.
13442323255454 is a deficient number, since it is larger than the sum of its proper divisors (6721161627730).
13442323255454 is an equidigital number, since it uses as much as digits as its factorization.
13442323255454 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6721161627729.
The product of its digits is 6912000, while the sum is 47.
Adding to 13442323255454 its reverse (45455232324431), we get a palindrome (58897555579885).
The spelling of 13442323255454 in words is "thirteen trillion, four hundred forty-two billion, three hundred twenty-three million, two hundred fifty-five thousand, four hundred fifty-four".
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