13442333544345 has 8 divisors (see below), whose sum is σ = 21507733670976. Its totient is φ = 7169244556976.

The previous prime is 13442333544337. The next prime is 13442333544373. The reversal of 13442333544345 is 54344533324431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13442333544345 - 2³ = 13442333544337 is a prime.

It is a super-2 number, since 2×13442333544345² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13442333544294 and 13442333544303.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 448077784797 + ... + 448077784826.

It is an arithmetic number, because the mean of its divisors is an integer number (2688466708872).

Almost surely, 2^{13442333544345} is an apocalyptic number.

13442333544345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13442333544345 is a deficient number, since it is larger than the sum of its proper divisors (8065400126631).

13442333544345 is an equidigital number, since it uses as much as digits as its factorization.

13442333544345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 896155569631.

The product of its digits is 12441600, while the sum is 48.

Adding to 13442333544345 its reverse (54344533324431), we get a palindrome (67786866868776).

The spelling of 13442333544345 in words is "thirteen trillion, four hundred forty-two billion, three hundred thirty-three million, five hundred forty-four thousand, three hundred forty-five".