Base | Representation |
---|---|
bin | 1100001110011100111000… |
… | …1010001100111010111010 |
3 | 1202121002012202200210100022 |
4 | 3003213032022030322322 |
5 | 3230220024312400132 |
6 | 44331205241210442 |
7 | 2555116326025661 |
oct | 303471612147272 |
9 | 52532182623308 |
10 | 13442411450042 |
11 | 4312992903253 |
12 | 1611290490a22 |
13 | 7667c9b43513 |
14 | 34688ab55dd8 |
15 | 184a04600e12 |
hex | c39ce28ceba |
13442411450042 has 8 divisors (see below), whose sum is σ = 20164005160032. Its totient is φ = 6721076396700.
The previous prime is 13442411450033. The next prime is 13442411450119. The reversal of 13442411450042 is 24005411424431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13442411449984 and 13442411450011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64534184 + ... + 64742147.
It is an arithmetic number, because the mean of its divisors is an integer number (2520500645004).
Almost surely, 213442411450042 is an apocalyptic number.
13442411450042 is a deficient number, since it is larger than the sum of its proper divisors (6721593709990).
13442411450042 is a wasteful number, since it uses less digits than its factorization.
13442411450042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 129328324.
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 13442411450042 its reverse (24005411424431), we get a palindrome (37447822874473).
The spelling of 13442411450042 in words is "thirteen trillion, four hundred forty-two billion, four hundred eleven million, four hundred fifty thousand, forty-two".
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