13442413301133 has 4 divisors (see below), whose sum is σ = 17923217734848. Its totient is φ = 8961608867420.

The previous prime is 13442413301099. The next prime is 13442413301143. The reversal of 13442413301133 is 33110331424431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13442413301133 - 2⁶ = 13442413301069 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13442413301094 and 13442413301103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442413301143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240402216853 + ... + 2240402216858.

It is an arithmetic number, because the mean of its divisors is an integer number (4480804433712).

Almost surely, 2^{13442413301133} is an apocalyptic number.

It is an amenable number.

13442413301133 is a deficient number, since it is larger than the sum of its proper divisors (4480804433715).

13442413301133 is an equidigital number, since it uses as much as digits as its factorization.

13442413301133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4480804433714.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13442413301133 its reverse (33110331424431), we get a palindrome (46552744725564).

The spelling of 13442413301133 in words is "thirteen trillion, four hundred forty-two billion, four hundred thirteen million, three hundred one thousand, one hundred thirty-three".