1344243314301 has 4 divisors (see below), whose sum is σ = 1792324419072. Its totient is φ = 896162209532.

The previous prime is 1344243314291. The next prime is 1344243314411. The reversal of 1344243314301 is 1034133424431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344243314301 - 2⁶ = 1344243314237 is a prime.

It is a super-2 number, since 2×1344243314301² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344245314301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224040552381 + ... + 224040552386.

It is an arithmetic number, because the mean of its divisors is an integer number (448081104768).

Almost surely, 2^{1344243314301} is an apocalyptic number.

It is an amenable number.

1344243314301 is a deficient number, since it is larger than the sum of its proper divisors (448081104771).

1344243314301 is an equidigital number, since it uses as much as digits as its factorization.

1344243314301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448081104770.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1344243314301 its reverse (1034133424431), we get a palindrome (2378376738732).

The spelling of 1344243314301 in words is "one trillion, three hundred forty-four billion, two hundred forty-three million, three hundred fourteen thousand, three hundred one".