Base | Representation |
---|---|
bin | 1100001110011100111110… |
… | …0001011011010010011101 |
3 | 1202121002021100201110202012 |
4 | 3003213033201123102131 |
5 | 3230220101141043141 |
6 | 44331211415241005 |
7 | 2555120024260616 |
oct | 303471741332235 |
9 | 52532240643665 |
10 | 13442434315421 |
11 | 43129a4800361 |
12 | 1611298079165 |
13 | 7668017bac27 |
14 | 34688dbc8c0d |
15 | 184a0661aceb |
hex | c39cf85b49d |
13442434315421 has 4 divisors (see below), whose sum is σ = 13442589750144. Its totient is φ = 13442278880700.
The previous prime is 13442434315399. The next prime is 13442434315433. The reversal of 13442434315421 is 12451343424431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13442434315421 - 214 = 13442434299037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13442434315481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77587565 + ... + 77760626.
It is an arithmetic number, because the mean of its divisors is an integer number (3360647437536).
Almost surely, 213442434315421 is an apocalyptic number.
It is an amenable number.
13442434315421 is a deficient number, since it is larger than the sum of its proper divisors (155434723).
13442434315421 is an equidigital number, since it uses as much as digits as its factorization.
13442434315421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155434722.
The product of its digits is 552960, while the sum is 41.
Adding to 13442434315421 its reverse (12451343424431), we get a palindrome (25893777739852).
The spelling of 13442434315421 in words is "thirteen trillion, four hundred forty-two billion, four hundred thirty-four million, three hundred fifteen thousand, four hundred twenty-one".
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