13442445503 has 4 divisors (see below), whose sum is σ = 13442941680. Its totient is φ = 13441949328.

The previous prime is 13442445449. The next prime is 13442445509. The reversal of 13442445503 is 30554424431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30554424431 = 373 ⋅81915347.

It is a cyclic number.

It is not a de Polignac number, because 13442445503 - 2⁶ = 13442445439 is a prime.

It is a super-2 number, since 2×13442445503² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442445509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204950 + ... + 262467.

It is an arithmetic number, because the mean of its divisors is an integer number (3360735420).

Almost surely, 2^13442445503 is an apocalyptic number.

13442445503 is a deficient number, since it is larger than the sum of its proper divisors (496177).

13442445503 is an equidigital number, since it uses as much as digits as its factorization.

13442445503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496176.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 13442445503 its reverse (30554424431), we get a palindrome (43996869934).

The spelling of 13442445503 in words is "thirteen billion, four hundred forty-two million, four hundred forty-five thousand, five hundred three".