Base | Representation |
---|---|
bin | 10011100011111011110… |
… | …011010100101011101111 |
3 | 11202111202101200102120211 |
4 | 103203323303110223233 |
5 | 134011013102103011 |
6 | 2505313015323251 |
7 | 166055606201401 |
oct | 23437363245357 |
9 | 4674671612524 |
10 | 1344254331631 |
11 | 479105586592 |
12 | 198638080527 |
13 | 999bb6995a3 |
14 | 490c2b92b71 |
15 | 24e7916eb21 |
hex | 138fbcd4aef |
1344254331631 has 2 divisors, whose sum is σ = 1344254331632. Its totient is φ = 1344254331630.
The previous prime is 1344254331619. The next prime is 1344254331683. The reversal of 1344254331631 is 1361334524431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344254331631 - 25 = 1344254331599 is a prime.
It is a super-2 number, since 2×13442543316312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344254331611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672127165815 + 672127165816.
It is an arithmetic number, because the mean of its divisors is an integer number (672127165816).
Almost surely, 21344254331631 is an apocalyptic number.
1344254331631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344254331631 is an equidigital number, since it uses as much as digits as its factorization.
1344254331631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 311040, while the sum is 40.
The spelling of 1344254331631 in words is "one trillion, three hundred forty-four billion, two hundred fifty-four million, three hundred thirty-one thousand, six hundred thirty-one".
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