Base | Representation |
---|---|
bin | 111110100110001111… |
… | …0001011111001011011 |
3 | 110211222110001111120101 |
4 | 1331030132023321123 |
5 | 4200301300431033 |
6 | 141431020240231 |
7 | 12466140241363 |
oct | 1751436137133 |
9 | 424873044511 |
10 | 134426967643 |
11 | 52012578481 |
12 | 220773a0077 |
13 | c8a40ba507 |
14 | 67134039a3 |
15 | 376b82797d |
hex | 1f4c78be5b |
134426967643 has 2 divisors, whose sum is σ = 134426967644. Its totient is φ = 134426967642.
The previous prime is 134426967599. The next prime is 134426967809. The reversal of 134426967643 is 346769624431.
It is a weak prime.
It is an emirp because it is prime and its reverse (346769624431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134426967643 - 29 = 134426967131 is a prime.
It is not a weakly prime, because it can be changed into another prime (134426947643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67213483821 + 67213483822.
It is an arithmetic number, because the mean of its divisors is an integer number (67213483822).
Almost surely, 2134426967643 is an apocalyptic number.
134426967643 is a deficient number, since it is larger than the sum of its proper divisors (1).
134426967643 is an equidigital number, since it uses as much as digits as its factorization.
134426967643 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15676416, while the sum is 55.
The spelling of 134426967643 in words is "one hundred thirty-four billion, four hundred twenty-six million, nine hundred sixty-seven thousand, six hundred forty-three".
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