Base | Representation |
---|---|
bin | 11001000010100010… |
… | …11010010010010110 |
3 | 1021200212120221210002 |
4 | 30201101122102112 |
5 | 210012414123014 |
6 | 10101540331302 |
7 | 654063404402 |
oct | 144121322226 |
9 | 37625527702 |
10 | 13443114134 |
11 | 577931868a |
12 | 27320a3b32 |
13 | 136312a408 |
14 | 917554102 |
15 | 53a2cedde |
hex | 32145a496 |
13443114134 has 4 divisors (see below), whose sum is σ = 20164671204. Its totient is φ = 6721557066.
The previous prime is 13443114127. The next prime is 13443114163. The reversal of 13443114134 is 43141134431.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13443114097 and 13443114106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360778532 + ... + 3360778535.
It is an arithmetic number, because the mean of its divisors is an integer number (5041167801).
Almost surely, 213443114134 is an apocalyptic number.
13443114134 is a deficient number, since it is larger than the sum of its proper divisors (6721557070).
13443114134 is an equidigital number, since it uses as much as digits as its factorization.
13443114134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6721557069.
The product of its digits is 6912, while the sum is 29.
Adding to 13443114134 its reverse (43141134431), we get a palindrome (56584248565).
The spelling of 13443114134 in words is "thirteen billion, four hundred forty-three million, one hundred fourteen thousand, one hundred thirty-four".
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