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1344311425145 = 51321198017603
BaseRepresentation
bin10011100011111111001…
…101000111100001111001
311202111220101010002011102
4103203333031013201321
5134011122211101040
62505322415141145
7166060201401653
oct23437715074171
94674811102142
101344311425145
11479134831807
121986532147b5
13999ca469630
14490ca5b56d3
1524e7e19b515
hex138ff347879

1344311425145 has 16 divisors (see below), whose sum is σ = 1745497492032. Its totient is φ = 988017428160.

The previous prime is 1344311425141. The next prime is 1344311425199. The reversal of 1344311425145 is 5415241134431.

It is not a de Polignac number, because 1344311425145 - 22 = 1344311425141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344311425099 and 1344311425108.

It is not an unprimeable number, because it can be changed into a prime (1344311425141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48995087 + ... + 49022516.

It is an arithmetic number, because the mean of its divisors is an integer number (109093593252).

Almost surely, 21344311425145 is an apocalyptic number.

It is an amenable number.

1344311425145 is a deficient number, since it is larger than the sum of its proper divisors (401186066887).

1344311425145 is a wasteful number, since it uses less digits than its factorization.

1344311425145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98017832.

The product of its digits is 115200, while the sum is 38.

Adding to 1344311425145 its reverse (5415241134431), we get a palindrome (6759552559576).

The spelling of 1344311425145 in words is "one trillion, three hundred forty-four billion, three hundred eleven million, four hundred twenty-five thousand, one hundred forty-five".

Divisors: 1 5 13 65 211 1055 2743 13715 98017603 490088015 1274228839 6371144195 20681714233 103408571165 268862285029 1344311425145