134431406143603 has 4 divisors (see below), whose sum is σ = 136967847769008. Its totient is φ = 131894964518200.

The previous prime is 134431406143591. The next prime is 134431406143649. The reversal of 134431406143603 is 306341604134431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134431406143603 - 2⁵ = 134431406143571 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134431406143603.

It is not an unprimeable number, because it can be changed into a prime (134431406143663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1268220812623 + ... + 1268220812728.

It is an arithmetic number, because the mean of its divisors is an integer number (34241961942252).

Almost surely, 2^{134431406143603} is an apocalyptic number.

134431406143603 is a deficient number, since it is larger than the sum of its proper divisors (2536441625405).

134431406143603 is an equidigital number, since it uses as much as digits as its factorization.

134431406143603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2536441625404.

The product of its (nonzero) digits is 746496, while the sum is 43.

The spelling of 134431406143603 in words is "one hundred thirty-four trillion, four hundred thirty-one billion, four hundred six million, one hundred forty-three thousand, six hundred three".