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134432656555531 = 1167157115179583
BaseRepresentation
bin11110100100010000001010…
…101111010111111000001011
3122121222122011222100021011111
4132210100022233113320023
5120110021040034234111
61153525302043311151
740213303356565405
oct3644201257277013
9577878158307144
10134432656555531
113991a629a78764
12130b1b4881b4b7
135a01c39569199
14252a80a86db75
151081d7ddc8a21
hex7a440abd7e0b

134432656555531 has 4 divisors (see below), whose sum is σ = 134432772902272. Its totient is φ = 134432540208792.

The previous prime is 134432656555529. The next prime is 134432656555541. The reversal of 134432656555531 is 135555656234431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134432656555531 - 21 = 134432656555529 is a prime.

It is a super-2 number, since 2×1344326565555312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134432656555501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56422635 + ... + 58756948.

It is an arithmetic number, because the mean of its divisors is an integer number (33608193225568).

Almost surely, 2134432656555531 is an apocalyptic number.

134432656555531 is a deficient number, since it is larger than the sum of its proper divisors (116346741).

134432656555531 is a wasteful number, since it uses less digits than its factorization.

134432656555531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116346740.

The product of its digits is 97200000, while the sum is 58.

The spelling of 134432656555531 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, six hundred fifty-six million, five hundred fifty-five thousand, five hundred thirty-one".

Divisors: 1 1167157 115179583 134432656555531