134433151101541 has 4 divisors (see below), whose sum is σ = 134433176003712. Its totient is φ = 134433126199372.

The previous prime is 134433151101533. The next prime is 134433151101559. The reversal of 134433151101541 is 145101151334431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134433151101541 - 2³ = 134433151101533 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134433151101541.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134433151101511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 581941 + ... + 16407466.

It is an arithmetic number, because the mean of its divisors is an integer number (33608294000928).

Almost surely, 2^{134433151101541} is an apocalyptic number.

It is an amenable number.

134433151101541 is a deficient number, since it is larger than the sum of its proper divisors (24902171).

134433151101541 is an equidigital number, since it uses as much as digits as its factorization.

134433151101541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24902170.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 134433151101541 in words is "one hundred thirty-four trillion, four hundred thirty-three billion, one hundred fifty-one million, one hundred one thousand, five hundred forty-one".