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13443322130999 is a prime number
BaseRepresentation
bin1100001110100000010001…
…1100001011001000110111
31202121011120020022011202122
43003220010130023020313
53230223410431142444
644331435452230155
72555151024501335
oct303500434131067
952534506264678
1013443322130999
11431330a970342
1216114a546b35b
137669137096a7
14346935a92b55
15184a5953c4ee
hexc3a0470b237

13443322130999 has 2 divisors, whose sum is σ = 13443322131000. Its totient is φ = 13443322130998.

The previous prime is 13443322130963. The next prime is 13443322131181. The reversal of 13443322130999 is 99903122334431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13443322130999 - 28 = 13443322130743 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13443322130999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13443322130099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721661065499 + 6721661065500.

It is an arithmetic number, because the mean of its divisors is an integer number (6721661065500).

Almost surely, 213443322130999 is an apocalyptic number.

13443322130999 is a deficient number, since it is larger than the sum of its proper divisors (1).

13443322130999 is an equidigital number, since it uses as much as digits as its factorization.

13443322130999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3779136, while the sum is 53.

The spelling of 13443322130999 in words is "thirteen trillion, four hundred forty-three billion, three hundred twenty-two million, one hundred thirty thousand, nine hundred ninety-nine".